Double format and can be easily manipulated using common arithmetic functions. For this, you can use the Replace function. A few of them are major, but most are just minor. To convert the string, you will have to remove one or both of them. CDbl(S) returns the double floating point value contained in S (localized). Lets make a Sega Genesis Emulator! (VB6 & VB.Net) Expert. The conversion to a double isn't working because there are two decimal points in your string. These slow functions are used to convert other data types to a string. My Contributions: Massive DirectX 2D Tutorials For VB5/VB6/VB.NET || 3D Engine In Pure VB || Friction Force || DJ Turntable Simulation || Scratching Wavs || Time Based Movement || Newton Physics Simulation || Managed Game Loop || Rigid Body Collision Detection || World of Warcraft RGB Battle System || Bosskillers (World of Warcraft 2D Clone) || Street Fighter Controls (Flawless Simulation) || A* Pathfinding (VB6 & VB.NET) *UPDATED || *NEW* Nintendo Entertainment System Emulator (VB6) || *NEW* Video Game Making Tips (VB6 & VB.Net) || World of Warcraft Spell Cooldown Effect (VB.Net 2008, 2010 & VB6) || *NEW* Flappy Bird (VB.Net) So my solution is write dot decimal number in a xml file and convert the readed string from the same xml file mystring.Replace('.', ',') Thanks Agat for suggestion to research the problem in xml context and because I didnt know visual studio doesnt respect the culture settings I have in my code. When your problem is solved, go up to Thread Tools and click on Mark Thread Resolved That way you can avoid saying "Dear so and so" in every post. Write posts like a conversation, not like an email. Convert String to Double in VB Dim vIn As String vIn -4.94065645841247E-324 comma or dot, it is culture depends Dim vOut As Double vOut CDbl(vIn). Be sure to use tags when posting code written in VB. Str2 = CStr(WorksheetFunction.Round(CDbl(Str1), 3))ĭigits = Digits & String(6 - 1 - Len(Exp) - Len(Digits), "0")ĭigits = Digits & ".- If you found any post that was useful, please consider rating their post ![]() Str2 = CStr(WorksheetFunction.Round(CDbl(Str1), 4)) MsgBox ("Number is too large to convert to 6 digits" & Str1) If InStrRev(Str1, ".",, vbTextCompare) = 0 Then Str1 = Replace(Str1, ",", ".",, , vbTextCompare)Įloc = InStrRev(Str1, "E",, vbTextCompare) ArrayToString, Procedure, Convert the passed array to a delimited string. For instance: a Convert.ToInt32('123.50') exception due to decimal point a. Declarations and private variables for the modStrings module. ![]() but according to MSDN optimized for use in VB. This is my code: Function GetSixDig(number As Double) As String I was just wondering how to correctly Convert string to date Convert integer to short Convert string to integer Convert string to double correctly without using any Ctypes of any sort. Imports MySql. So the number this function produces will be inserted for example in columns 11 to 16, right justified. The input on each line follows fixed position input. Now it uses a text file as input, and each line represents a card. I tried use CSng, CCur, but the result is not expected. This program provides input to a structural analysis program that originated in the 80's. I need to convert the string that has value '647.340.200' to double. I am wondering if there is a much easier way to do this. This made the function grow much bigger than I anticipated. The double can be a large value, a small value, positive or negative or in scientific notation. This seemed like a very simple task in the beginning, but I ran in to many issues. Your code seems to be converting the double byte unicode string into a single byte representation of the string, this will result in garbage for any character with a codepoint > 255. ![]() I am converting a double to a string with a fixed length (6 characters in this case).
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